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separable closure

Last updated January 27, 2022

Idea

The separable closure of $F$, denoted $F^\text{sep}$, is the “biggest Galois extension of $F$”. This is the result of two facts:

  1. $F^\text{sep}$ is the maximal separable extension of $F$
  2. $F^\text{sep}$ is a normal extension

Definition

Equivalently, let us define an element to be separable over $F$ if its minimal polynomial is separable. Then

Remark. The requirement of being separable (in addition to being separably closed) is not redundant: take the separable closure and add a transcendental element. The result is separable closed but not separable. We have implied the following:

  1. $F^\text{sep}$ is the maximal separable extension of $F$.

Properties

  1. $F^\text{sep}$ is the maximal separable extension of $F$.
  2. $F^\text{sep}$ is normal.
  3. $F^\text{sep}/F$ is Galois, and also the maximal Galois extension of $F$.

Proofs 2 It suffices to show that if an irreducible polynomial in $F$ has a root in $F^\text{sep}$, then all roots are contained there. Let $P$ be an irreucible polynomial in $F$. If it has a root in $F^\text{sep}$, then that root must be separable, meaning its minimal polynomial is separable. The minimal polynomial is unique, so it must be $P$. But then all other roots of $P$ are seperable, hence they all belong to $F^\text{sep}$.


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